64=-16t^2+32t+48

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Solution for 64=-16t^2+32t+48 equation: 



64=-16t^2+32t+48

We move all terms to the left:

64-(-16t^2+32t+48)=0

We get rid of parentheses

16t^2-32t-48+64=0

We add all the numbers together, and all the variables

16t^2-32t+16=0

a = 16; b = -32; c = +16;
Δ = b2-4ac
Δ = -322-4·16·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{32}{32}=1$

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